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96=24x^2
We move all terms to the left:
96-(24x^2)=0
a = -24; b = 0; c = +96;
Δ = b2-4ac
Δ = 02-4·(-24)·96
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*-24}=\frac{-96}{-48} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*-24}=\frac{96}{-48} =-2 $
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